1 Apr 2000 21:44
Curious fact
Michael Barr <barr <at> barrs.org>
2000-04-01 19:44:04 GMT
2000-04-01 19:44:04 GMT
Has anyone seen this before, or can anyone give a principled
explanation. Begin with the following observation. Suppose
del del
... -----> (C_n,d) -----> (C_{n-1},d) ---> ... ---> (C_0,d) --> 0
is a chain complex of differential abelian groups, except that we
assume d.del = -del.d. Suppose (C_n,d) is exact for each n. Let C be
the direct sum of the C_n with boundary given by the matrix
( d 0 0 ... )
( del d 0 ... )
( 0 del d ... )
( . . . . )
( . . . . )
( . . . . )
The finite truncations F^n = C_0 +...+ C_n are readily
shown to be exact: F^0 = C_0 is by hypothesis and there is an exact
sequence 0 --> F^{n-1} --> F^n --> C_n --> 0. AB5 now shows that
the direct limit, which is C, is exact.
Of course, this is going to be false for a category, such as compact
abelian groups, that is not AB5. Except it is true. Using duality, we
can translate it to the following statement for abelian groups. Suppose
del del
... <----- (C_n,d) <----- (C_{n-1},d) <--- ... <--- (C_0,d) <-- 0
is a cochain complex of differential abelian groups, except that we
assume d.del = -del.d. Suppose (C_n,d) is exact for each n. Let C be
the direct product of the C_n with boundary given by the matrix
( d del 0 ... )
( 0 d del ... )
( 0 0 d ... )
( . . . . )
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