Hi ZSH users, Autocompletion for umount lists mount points clipped at the first space. For example, if I have "/Volumes/Media Drive" and "/Volumes/Media Disk", autocomplete for amount will only list a single "/Volumes/Media". Is there a fix or workaround for this? --David
Hello, I just notice filename globbing doesn't occur in my script, like v=* but it works in the interactive shell. Althoug I can make it work by "setop glob_assign" or use "v=(*)", but it looks like the behavior's diversity is a little strange. Any thoughts? Thanks.
> > echo a/f/b/b/x<TAB> > > Doesn't help here, for two reason: > > (1) At least in my version of zsh (4.3.12), this would not expand the > > interim directories (f,b,b). > Does your zsh configuration include installing the completion system > (the "compinit" command)? Doesn't look like: (1;0) /cygdrive/c> type compinit compinit not found However I think I should have the completion system installed: (1;1) /cygdrive/c> zmodload zsh/compctl zsh/complete zsh/main zsh/zle Is there an additional module that I need here? > > (2) Even if I could do TAB completion on directories within the path, > > this is not what I'm looking for, because it is still cumbersome to > > type. > You might want to look at named directories Thank you for this suggestion. I'll have a look at it!(Continue reading)
If I have a completion function like this:
_k () { _arguments --r1-word --r2-word }
and I press TAB at the end of the following commandline:
% k --r
then I get
% k --r-word
Another tab beeps and lists the choices, a third tab beeps and chooses
--r1-word, and thereon tabs simply cycle between the two. That's more or
less expected.
If I define _k instead as
_k () { _arguments --r1-word --really-r1-word }
then the second tab simply completes --r1-word, which seems wrong to me.
This is all with "zsh -f", with nothing but
autoload -Uz compinit
compinit -i
compdef _k k
run before attempting the completion.
(Continue reading)
> dear Sir/Madam > > I am using zsh and interested in it, so I'd like to learn the one more and > more. please participate me in your activity. > > thanks > > > Takeshi A good place to start http://zshwiki.org/ -- -- zzapper http://zzapper.co.uk/ Technical Tips
Within a script, I have need to store the 4th word in the first line of
a file.
Of course this is trivial to implement. However, I'm curious whether
there exists a better way to implement than what I found.
My current solution goes like this:
# $1 is the filename
line=$(head -n 1 $1)
field=${lin[(w)4]}
This is OK, but this needs an auxiliary variable 'line'.
I could also do it like this:
field=$(head -n 1 $1|cut -f 4 -d ' ')
No aux variable, but needs a pipe
So I wonder, whether there is a elegant "zsh" solution, which solves
this in a more elegant way?
Ronald
--
--
Ronald Fischer <ronaldf <at> eml.cc>
+ If a packet hits a pocket on a socket on a port,
+ and the bus is interrupted and the interrupt's not caught,
+ then the socket packet pocket has an error to report.
+ (cited after Peter van der Linden)
(Continue reading)
I have a folder which has a lot of txt files, and in that folder are a lot of duplicate files. Most of the duplicates are numbered like this: 10-(Continue reading)6- Make a universal 10-6-7 Snow Leopard installer-1.txt 10-6- Make a universal 10-6-7 Snow Leopard installer-2.txt 10-6- Make a universal 10-6-7 Snow Leopard installer-3.txt 10-6- Make a universal 10-6-7 Snow Leopard installer-4.txt 10-6- Make a universal 10-6-7 Snow Leopard installer.txt Not not all of them. For example, I might have another identical file named todo-make-snowleopardinstaller.txt What I want to do is go through the entire folder and find all duplicate files (files with identical md5sum). Then I want to keep ONLY the one with the shortest filename. Here's what I have so far #!/bin/zsh DIR=/Users/luomat/Dropbox/txt/ # to avoid 'arg list too long' # note that 'gmd5sum' prints the sum # and then two spaces, and then the filename ALL=$(find $DIR -type f -print0 | xargs -0 gmd5sum)
I have a set of directory structures like this: aaa/foo/bar/baz/xxx bbb/foo/bar/baz/yyy ccc/foo/bar/baz/zzz etc. I'm looking for a way to make typing easier on the command line, in order to not have to type foo/bar/baz all the time. Of course I can achieve this by setting a shell variable in my .zshrc: X=foo/bar/baz Then I can do for instance ls aaa/$X/xxx Now I recently learned about global aliases, which permit alias substitution to be done within the command line, and I thought that I maybe could use this. Here was my (failed) attempt: alias -g X=foo/bar/baz # Does NOT work at hoped ls aaa/X/xxx X is not substituted, because it is not a word on its own (not surrounded by spaces).(Continue reading)
I have a set of directory structures like this: aaa/foo/bar/baz/xxx bbb/foo/bar/baz/yyy ccc/foo/bar/baz/zzz etc. I'm looking for a way to make typing easier on the command line, in order to not have to type foo/bar/baz all the time. Of course I can achieve this by setting a shell variable in my .zshrc: X=foo/bar/baz Then I can do for instance ls aaa/$X/xxx Now I recently learned about global aliases, which permit alias substitution to be done within the command line, and I thought that I maybe could use this. Here was my (failed) attempt: alias -g X=foo/bar/baz # Does NOT work at hoped ls aaa/X/xxx X is not substituted, because it is not a word on its own (not surrounded by spaces).(Continue reading)
$ foo="ONE TWO thRee FoUR"
$ print -r -- "${(C)foo}"
will output this:
One Two Three Four
but this:
$ foo="ONE TWO thRee FoUR's"
$ print -r -- "${(C)foo}"
will give this:
One Two Three Four'S
Note the S is capitalized
$ foo="ONE TWO thRee FoUR's.pdf"
$ print -r -- "${(C)foo}"
will give this:
One Two Three Four'S.Pdf
Note that the P in PDF and the S after ' are capitalized.
Is there any way to avoid that?
(Continue reading)
Hi
This is a PHP regexp /^FLOW_([0-9]{3}).csv$/
I can simulate this in a brute fashion
> ls FLOW_[0-9][0-9][0-9].csv
Is it possible to use a count 3 in ZSH FNG?
--
--
zzapper
http://zzapper.co.uk/ Technical Tips
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