В Сбт, 01/08/2009 в 07:48 -0400, Chris Wj пишет:

> I'm looking for the best way to split an xml file with many children
> into multiple files with the same parent tags but individual children.

...

> Should I use lxml.etree to find the line numbers and then just use
> file operations? You guys think that is most efficient?

I think that the simplest way to split the file is to remove all 'child'
element from parsed document and serialize document with different
childs.

In [3]: parsed = etree.parse('q.xml')
In [4]: root = parsed.getroot()
In [5]: childs = parsed.findall('child')
In [6]: for child in childs: root.remove(child)
In [7]: for num, child in enumerate(childs):
   ...     root.append(child)
   ...     f = codecs.open('file1%s.xml' % num, 'w', encoding='utf-8')
   ...     f.write(etree.tounicode(parsed))
   ...     f.close()
   ...     root.remove(child)

This solution works incorrect with tail text or nodes after 'child'
nodes. I don't know if it's critical for you, but the next XML will be
split in wrong way.
 <parent>
     <child>....</child>
     1234
     <child>....</child>
     <some-tag>....</some-tag>
 </parent>

If you need to split big XML files, it's much better to use SAX
interface. But SAX reader/writer is a way harder to implement.