Krishna Nair | 1 Oct 22:53
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How can i derive a equation for my graph

I have drawn a graph with the data given below and would like the software to give a equation for my graph. Can it do that?

 

Wind Speed (m/s)

Power Output (kW)

0

0

1

0

2

0

3

0

4

4.9

5

18.2

6

34.1

7

59.6

8

86.5

9

125.9

10

160.9

11

190.6

12

221.2

13

244.4

14

255.5

15

263

16

267.6

17

272.2

18

272.3

19

272.4

20

273.5

 

Regards,

 

Krish

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Ivan Johansen | 6 Oct 07:59
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Re: Boxed axes style

plasteck wrote:
> When I use boxed axes style and I have text label, I cannot use
> PLecement->Below x-axis/Left of y-axis because it turns invisible. I
> know that it is placed in place which is not shown but I would rather
> that axes move a little to make text label visible.

Thanks for the suggestion. I will see what I can do about it.

Best regards
Ivan Johansen

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Ivan Johansen | 6 Oct 08:15
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Re: How can i derive a equation for my graph

Krishna Nair wrote:
> I have drawn a graph with the data given below and would like the 
> software to give a equation for my graph. Can it do that?

Yes, first you add your points to a point series. Next you can use 
"Function|Insert trendline" to create a line of best fit. You may want 
to check the help for this dialog as it has several options.

Best regards
Ivan Johansen

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Tom Gettys | 6 Oct 16:58
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Re: How can i derive a equation for my graph

Hi Ivan,
I tried that using the data that was provided by Krishna, but was unsuccessful.

The data plots as an 'S' curve, so a logistic model is implied.  Since that is not one of the built-in models I
tried the user-defined tab, which offers a growth-saturation model.  I could not figure out how to get it to
match the data, even slightly.  

I understand that it is determined by the initial guesses, but I could find none that worked.  I also tried
entering a more traditional logistic model that has 3 parameters, but there was some error message
(something about a list, error code -1; I forget now).

Do you have any suggestions?

Tom Gettys
Lane Community College
email:  gettyst <at> lanecc.edu
phone: (541) 463-3147
office: Bldg. 16/267

To dream of the person you would like to be is to waste the person you are.
>>> Ivan Johansen <graph <at> padowan.dk> 10/05/08 11:18 PM >>>
Krishna Nair wrote:
> I have drawn a graph with the data given below and would like the 
> software to give a equation for my graph. Can it do that?

Yes, first you add your points to a point series. Next you can use 
"Function|Insert trendline" to create a line of best fit. You may want 
to check the help for this dialog as it has several options.

Best regards
Ivan Johansen

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Ivan Johansen | 8 Oct 22:34
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Re: How can i derive a equation for my graph

Tom Gettys wrote:
> I tried that using the data that was provided by Krishna, but was
> unsuccessful.

I admit that creating user defined trendlines are not as easy as I could 
hope. I have some ideas how to improve it though.

As you say it is a logistic function. In the Insert trendline dialog, 
you can add the model $a*$b^x/($c+$d^x). I think the default guess is 
good enough.

When I use this model I get the function
f(x)=1.1713331*1.0026039^x/(0.0044819577+0.55890587^x)

This seems to fit the data very well.

Best regards
Ivan Johansen

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Tom Gettys | 8 Oct 22:36
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Re: How can i derive a equation for my graph

Thanks much Ivan!
 
Tom Gettys
Lane Community College
email:  gettyst <at> lanecc.edu
phone: (541) 463-3147
office: Bldg. 16/267

To dream of the person you would like to be is to waste the person you are.

>>> Ivan Johansen <graph <at> padowan.dk> 10/8/2008 1:34 PM >>>
Tom Gettys wrote:
> I tried that using the data that was provided by Krishna, but was
> unsuccessful.

I admit that creating user defined trendlines are not as easy as I could
hope. I have some ideas how to improve it though.

As you say it is a logistic function. In the Insert trendline dialog,
you can add the model $a*$b^x/($c+$d^x). I think the default guess is
good enough.

When I use this model I get the function
f(x)=1.1713331*1.0026039^x/(0.0044819577+0.55890587^x)

This seems to fit the data very well.

Best regards
Ivan Johansen


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Mohamed Aly | 13 Oct 12:33

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