Re: (no subject)

Margie Wall wrote:
> I am unable to load your program. I have Windows XP and the message 
> states "The application failed to initialize properly (0xc0000005)." Can 
> you provide any sugestions? Thank you.

My best suggestion is to download the program again. I don't know why 
this happens but it seems that sometimes only about 700 kB of the 
program is downloaded. It usually helps to try again later.

Alternatively you can try to download it from SourceForge at 
http://sf.net/projects/graph

Best regards
Ivan Johansen

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Question on graphing and shading

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Fwd: Question on graphing and shading

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Re: Question on graphing and shading

hfal50 <at> aol.com wrote:
> I have been using your software for my Algebra I class, and it is great 
> - thank you so much!
> 
> I am having problems figuring out how to do a function graph with 
> shading though, can you help me and give me some instructions on how to 
> do it?
> 
> I need to graph 3x - 4y <12 and separately 4x + y >= 4.

The easiest way is to use Function|Insert relation and enter 3x-4y<12 as 
the relation. The same can be done for the other inequality.

Best regards
Ivan Johansen

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Solving by Graphing: System of Linear Equations

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Re: Solving by Graphing: System of Linear Equations

hfal50 <at> aol.com wrote:
 > Please note the following examples:
 >
 > 1) 2x + y =2             Solutions: (0,2) and (1,0)
 >     2x + y =4             Solutions: (0.4) and (2,0)

You have two possibilities:
1. You can use "Function|Insert relation" to create a relation, and just
enter the equation, e.g. "2x + y = 2" or "2x + y = 4". You can then
visually see the solutions and where they intercept.

2. Alternatively you can convert the equations to functions:
f(x) = 2 - 2x
f(x) = 4 - 2x

You can then use "Function|Insert function" to insert them in Graph.
Calc|Evaluate can be used to find the solutions and interceptions. If
you choose Function as Snap to, then you can enter x=0 to find the
crossing with the y-axis. If you choose x-axis and click on the graphing
area Graph, will find the crossing with the x-axis. If you choose
Intersection and click on the graphing area, Graph will find the nearest
intersection with the other functions.

Best regards
Ivan Johansen

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Re: Solving by Graphing: System of Linear Equations

hfal50 <at> aol.com wrote:
> Please note the following examples:
> 
> 1) 2x + y =2             Solutions: (0,2) and (1,0)
>     2x + y =4             Solutions: (0.4) and (2,0)

You have two possibilities:
1. You can use "Function|Insert relation" to create a relation, and just 
enter the equation, e.g. "2x + y = 2" or "2x + y = 4". You can then 
visually see the solutions and where they intercept.

2. Alternatively you can convert the equations to functions:
f(x) = 2 - 2x
f(x) = 4 - 2x

You can then use "Function|Insert function" to insert them in Graph. 
Calc|Evaluate can be used to find the solutions and interceptions. If 
you choose Function as Snap to, then you can enter x=0 to find the 
crossing with the y-axis. If you choose x-axis and click on the graphing 
area Graph, will find the crossing with the x-axis. If you choose 
Intersection and click on the graphing area, Graph will find the nearest 
intersection with the other functions.

Best regards
Ivan Johansen

-------------------------------------------------------------------------
This SF.net email is sponsored by: Microsoft
Defy all challenges. Microsoft(R) Visual Studio 2005.
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Re: Solving by Graphing: System of Linear Equations

hfal50 <at> aol.com wrote:
> Please note the following examples:
> 
> 1) 2x + y =2             Solutions: (0,2) and (1,0)
>     2x + y =4             Solutions: (0.4) and (2,0)

You have two possibilities:
1. You can use "Function|Insert relation" to create a relation, and just
enter the equation, e.g. "2x + y = 2" or "2x + y = 4". You can then
visually see the solutions and where they intercept.

2. Alternatively you can convert the equations to functions:
f(x) = 2 - 2x
f(x) = 4 - 2x

You can then use "Function|Insert function" to insert them in Graph.
Calc|Evaluate can be used to find the solutions and interceptions. If
you choose Function as Snap to, then you can enter x=0 to find the
crossing with the y-axis. If you choose x-axis and click on the graphing
area Graph, will find the crossing with the x-axis. If you choose
Intersection and click on the graphing area, Graph will find the nearest
intersection with the other functions.

Best regards
Ivan Johansen

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Defy all challenges. Microsoft(R) Visual Studio 2005.
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jpeg import

Hi,
Is it possible to import an image (jpeg) into graphit.
For example if you wanted to find the function model of` a bridge

Peter

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Re: jpeg import

radonich <at> ihug.co.nz wrote:
> Hi,
> Is it possible to import an image (jpeg) into graphit.
> For example if you wanted to find the function model of` a bridge

No, but if you can find some data points and enter them into Graph, then 
Graph should be able to find the function for you.

Best regards
Ivan Johansen

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