Hi Dylan,
Probably you have cleared your doubt but I'll try to
expound how I see the question. The most important thing is you firstly have to
think if you are dealing with flux or energy.
The flux is something (let say, particles or light photons)
coming through a normal surface to the beam (for example, persons through a
door). Therefore the unit of flux has to be something like particles per
squared meter and per second (how many particles have reached the normal
surface in a second). In case of light (photons) we talk in terms of energy to count
the particles, so we have J/m2*s = W/m2 (because W = J/s). Then, when you
measure the solar radiation with a sensor, the measurement is usually in units
of flux [W/m2]. What does it mean? Let suppose in a given moment the sensor
reads 500 W/m2. That equals to 500 J/s/m2 = 500 J/m2/s, i.e. in a second you have
received 500 Joules per squared meter so, in 2 seconds, you will have 1000
joules in a squared meter. In 3 seconds you will have 1500 joules in a squared
meter and so on. Now we have sum (or integrated) the flux throw the time and
the magnitude can be seen as energy per unit of surface in a certain period of
time, let say hour, day, month,…
Watts per hour is a measurement of energy used in engineering not in
science. The only reason I think is because the magnitude of its value is more appropriate
than J or MJ. The equivalence is 1 Wh = (1 J/s)*3600 s = 3600 J = 0.0036 MJ
I work with radiometric sensors and sometimes I have
used r.sun. The approach I follow is to express both in J/m2/dia. With r.sun
the output is in Wh/m2/dia so directly multiply by 0.0036 and you will have
MJ/m2/dia and will know how much energy you have in a squared meter when the
day finish. Now let suppose you are getting a measurement every 10 minutes,
i.e. every 600 seconds. In that lapse of time you will have S[W/m2]*600seconds,
where S is the measurement. In a day you will have Sday[J/m2/dia] = S1*600s +
S2*600s + S3*600s + … and so on for all measurements in the day.
________________________________
José A. Ruiz Arias
Departamento de Física
Escuela Politécnica Superior
Edificio A-3, Campus Lagunillas
Universidad de Jaén
23071 Jaén Spain
Tlf. +34 953212474
Email: jararias <at> ujaen.es
_____________________________________
> -----Mensaje original-----
> De: grassuser-bounces <at> grass.itc.it
[mailto:grassuser-bounces <at> grass.itc.it]
> En nombre de Dylan Beaudette
> Enviado el: jueves, 30 de noviembre de 2006 22:55
> Para: Glynn Clements
> CC: grassuser <at> grass.itc.it; GRASS devel
> Asunto: Re: [GRASS-user] Clarification on units used in r.sun
>
> On Wednesday 29 November 2006 12:31, Glynn Clements wrote:
> > Dylan Beaudette wrote:
> > > Quick question on the units used for the ouput of r.sun
in mode 2
> (daily
> > > sums):
> > >
> > > In the manual pages for r.sun, the following 'unit' is
included in the
> > > description:
> > > ----------------------------
> > > The solar radiation maps for given day are computed
integrating the
> > > relevant irradiance between sunrise and sunset times for
given day.
> The
> > > user can set finer or coarser time step step used for
all-day
> radiation
> > > calculations. A default value of step is 0.5 hour.
Larger steps (e.g.
> > > 1.0-2.0) can speed-up calculations but produce less
reliable results.
> The
> > > output units are in Wh per squared meter per given day
[Wh/(m*m)/day].
> > > -------------------------
> > >
> > > Is one to interpret this as "watt-hour per square
meter per day" ?
> > > This would seem a little odd, as the the unit
'watt-hour' is not an SI
> > > unit.
> >
> > More odd (to me) is having (different) units of time in both
the
> > numerator and denominator. I would have thought it more
logical to
> > divide the result by 24 to give Watts per square metre
[W/(m^2)].
>
> I need to check with some local experts, but judging from some
recent
> tests -
> the output from r.sun is comparible to that from a weather
station, with
> *hourly* averaged data in W/(m^2) which i think is analogous to
the
> Wh/(m^2)
> units that r.sun uses.
>
> --
> Dylan Beaudette
> Soils and Biogeochemistry Graduate Group
> University of California at Davis
> 530.754.7341
>
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